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A secondary wastewater treatment process consists of a complete-mix circular bio

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A secondary wastewater treatment process consists of a complete-mix circular biological reactor and associated secondary clarifier. This process has an influent flow of 2.5 ML/day and maintains a mixed liquor volatile suspended solids concentration of 2850 mg/L. The secondary clarifier produces an effluent stream of 2.0 ML/day with negligible suspended solids (assume 0 mg/L) and a sludge of VSS 6580 mg/L. Following effective primary treatment, influent to the activated sludge process has negligible concentration of suspended solids (assume 0 mg/L) and a BOD of 600 mg/L. This system is operated to maintain constant volume in the process tanks and constant MLSS concentration.
Question: calculate RAS and WAS flow rate with above data (I asked a few people, they use 10^6/6580 to calculate VSS settled volume first and RAS=volume*(Qi-Qe)/(1000-volume), shouldn’t SVI be used for this question, please provide explaination I’m too confused)

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